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3 years ago

5

Sin^2 (theta)-cos^2 (theta)=0

1 answer:

yanalaym [24]3 years ago

8 0

Hope this helps you.

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Find the area for the following figure.<br> O 124. 86 cm2<br> 62.93 cm2<br> 26.5 cm2<br> 137.45 cm2

Semmy [17]

The answer is 62.93

8 0

2 years ago

Sandra exerci 2/3 hours every day for two weeks while she was on vacation how many hours did Sandra exercise during her vacation

vagabundo [1.1K]

I think the us 1 1/3. 2/3 x 2/1=4/3=1 1/3. Hope it helps and I hope it right.

3 0

2 years ago

Find a ·<br> b. |a| = 80, |b| = 50, the angle between a and b is 3π/4.

mart [117]

Answer:

$a\cdot b=-2000\sqrt{2}$

Step-by-step explanation:

Given information: |a| = 80, |b| = 50, the angle between a and b is 3π/4.

We need to find the dot product a · b.

The formula of dot product is

$a\cdot b=|a||b|\cos \theta$

where, θ is the angle between a and b.

Substitute the given values in the above formula.

$a\cdot b=(80)(50)\cos (\frac{3\pi}{4})$

$a\cdot b=4000\cos (\pi-\frac{\pi}{4})$

$a\cdot b=-4000\cos (\frac{\pi}{4})$ $[\because \cos (\pi-\theta)=-\cos \theta]$

$a\cdot b=-4000\frac{1}{\sqrt{2}}$

$a\cdot b=-\frac{4000}{\sqrt{2}}$

Rationalize the above equation.

$a\cdot b=-\frac{4000}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}$

$a\cdot b=-\frac{4000\sqrt{2}}{2}$

$a\cdot b=-2000\sqrt{2}$

Therefore, the value of a · b is $a\cdot b=-2000\sqrt{2}$ .

7 0

3 years ago

Read 2 more answers

1.06t can be written as (1.061/2)2t to give the approximate equivalent monthly interest rate based on an annual rate of 6%. Use

Tema [17]

Answer: $1.06^t$ .

Step-by-step explanation: We are given expression $1.06^t$ .

And $1.06^t$ expression is converted in $(1.06^{1/2})^{2t}$ .

Now, we need to transform the expression into a single exponent expression using the properties of exponents.

We know, according to the properties of exponents

$(a^m)^n = a^{m\times n}$

Applying same rule in given expression, we get

$(1.06^{1/2})^{2t} = (1.06)^{\frac{1}{2} \times 2t}$

On simplifying exponents, we would get t in exponent.

= $1.06^t$ .

5 0

3 years ago

Read 2 more answers

Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$

7 0

3 years ago