It would take about 63 hours...
Answer:
(7a^2 + 8b^2 + 5ab) (7a^2 + 8b^2 - 5ab)
Step-by-step explanation:
Dado que ambos términos son cuadrados perfectos, puede factorizar utilizando la fórmula de la diferencia de cuadrados, a^2 - b^ 2 = (a + b) (a - b), donde a = 7a^2 + 8b^2 y b = 5ab.
English: Since both terms are perfect squares you can factor using the difference of squares formula, a^2 - b^2 = (a + b)(a - b), where a = 7a^2 + 8b^2 and b = 5ab.
A. Constant of proportionality in this proportional relationship is; k=5
B. Equation to represent this proportional relationship is : c=t/k
Step-by-step explanation:
A.Given that : the amount she pays each month for international text messages is proportional to the number of international texts she sends, then
$3.20 k = 16 ---------where k is the constant of proportionality
k= 16/3.20 =5
k=5
B. Let c be the cost of sending the texts per month and t be the number of texts sent per month , so
c=t/k
c=t/5 ---------- is the proportionality relationship.
For t=16 , c= 16/5 =$3.20
Learn More
Proportionality :brainly.com/question/11490054
Keywords: cell phone plan, month, international texts, proportional,paid
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First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
The square root of 255+266 is 241. I can't help you with shortcuts as I'm bad at explaining, but I'm sure there are websites that can help you.
