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3 years ago

Need help on solving problems with comon tangents

Mathematics

1 answer:

Orlov [11]3 years ago

3 0

First, find angle ECD using tan^-1(6/4), we get angle as 56.31

Now by proportionate, angle ECD and angle EBA are equal.

Hence you can use tan to find AB i.e, AB = 18/tan(56.31)= 12

Therefore, AB = 12

You might be interested in

The sum of a two digit number is 18. If the digits are reversed, the number remains the same. Find the number.

Yanka [14]

Answer: 99

Explanation: 9+9 = 18
and when you switch the order of the digits, it is still 99.

Hope that helps ;)

4 0

3 years ago

What is the justification for each step in the solution of the equation?<br><br> 4(4x+6)−7=77−4x

zepelin [54]

Answer:

20x + 17 = 77 --> Addition Property of Equality:

You are adding (Addition Property) 4x to both sides of the equal sign (Equality).

20x = 60 --> Subtraction Property of Equality:

You subtracted (Subtraction Property) 17 from both sides of the equal sign (Equality).

x = 3 --> Division Property of Equality:

You divided (Division Property) 20 from both sides of the equal sign (Equality) to completely isolate the variable x.

6 0

2 years ago

A bag contains yellow marbles and red marbles, 77 in total. The number of yellow marbles is 5 more than 3 times the number of re

bulgar [2K]

Answer:

Step-by-step explanation:

yellow marbles=5+ 3r(r is the number of red marbles)

red marbles=3r

3r+3r+5=77

6r=77-5

6r=72

r=72/6=12

yellow marbles = 5 + 3r

5+ 12 x 3

5+ 36

=41

8 0

2 years ago

What is the slope of the line that contains the point (-2, 3) and (1,9)

erma4kov [3.2K]

The slope is:(9-3)/(1-(-2))=6/3=2

7 0

2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago