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schepotkina [342]

3 years ago

13

the area of a rectangle is 56 centimeters. The length is 2 centimeters more than x and the width is 5 Centimeters less than twic

e X. Solve for x. Round to the nearest whole number

1 answer:

Verdich [7]3 years ago

4 0

Okay, so...
length = x+2
width = 2x-5

Multiply these
x+2(2x-5)
x + 4x - 10
5x - 10 = 56

5x - 10 = 56
+ 10 + 10

5x = 66

x = 11.20

:D

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vivado [14]

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5 0

2 years ago

What is the slope of a line perpendicular to y = -7/4x?

dexar [7]

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6 0

2 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

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Gwar [14]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

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Dovator [93]

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3 0

2 years ago