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Yakvenalex [24]

3 years ago

14

If you deposit $1,000 ir an account that pays 6% annual interest compounded continuously, what will the balance be after five ye

ars?

1 answer:

alexira [117]3 years ago

7 0

Answer:

If you know 6% of 1000 is 60 so each year 60 will add so 60x5 is 300 so you will earn 300 in 5 years.

Step-by-step explanation:

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What is the mode for the following set of data? 2, 5, 7, 8, 11, 11, 12

aleksley [76]

Mode = 11

Reason: 11 appeared twice, which is the most frequent number observed in this set of data.

8 0

3 years ago

How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1

swat32

There are infinitely many solutions.

Algebraically, we can eliminate $z$ and try to solve for $x,y$ :

$x+y+z=1\implies z=1-x-y$

Then

$x^2+y^2+(1-x-y)^2=1$

$\implies x^2+y^2+1-2x+x^2-2y+y^2+2xy=1$

$\implies x^2-x+y^2-y+xy=0$

which is the equation of an ellipse.

5 0

3 years ago

What is 6+9+4+1+10? Please explain?

Viktor [21]

30, 6+9= 15+4= 19+1= 20+10= 30

3 0

3 years ago

Read 2 more answers

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0

3 years ago

If a rectangular region has perimeter p inches and area a square inches, is the region square?

Flura [38]

If this is all the information you have, it is not enough to conclude the region is square. we need more information

8 0

3 years ago