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3 years ago

10

This is a physical process which takes place when rocks are broken down without any change in their chemical nature. the rocks a

re broken apart by physical force,

2 answers:

Fudgin [204]3 years ago

7 0

Erosion is the process when the physical world breaks apart rocks by water air and movement

harkovskaia [24]3 years ago

4 0

Answer: Mechanical Weathering

Explanation:

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Two loudspeakers face each other, vibrate in phase, and produce identical 406 Hz tones. A listener walks from one speaker toward

Pavlova-9 [17]

Answer:

1.21 m/s

Explanation:

Given :

2 loudspeakers

F2 - F1 = 2.86 Hz

Speed of sound, V = 343

Fo = frequency when listener is at rest = 406Hz

To obtain the walking speed Vo, speed as observer moves away from speaker ;

Vo = [(F2 - F1) * V] ÷ 2 * Fo

Vo = [2.86 * 343] ÷ (2 * 406)

Vo = 980.98 / 812

Vo = 1.2081034

Vo = 1.21 m/s

3 0

3 years ago

Someone help me?

kap26 [50]

Answer:

-27.3 m/s

Explanation:

Given:

y₀ = 38 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (-9.8 m/s²) (0 m − 38 m)

v = -27.3 m/s

Or, you can solve with energy.

PE = KE

mgh = ½ mv²

v² = 2gh

v = -27.3 m/s

3 0

3 years ago

The Starship Enterprise speeds past an asteroid at 0.920c. If an observer on the asteroid sees 10.0 seconds pass on her watch, h

lukranit [14]

Answer:

25.52 seconds

Explanation:

Speed of space ship = 0.92 c = v

c = Speed of light

Time observed from asteroid = Δt = 10 seconds

Time dilation

$\Delta t'=\frac{\Delta t}{\sqrt{1-\frac {v^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-\frac {0.92^2c^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-0.92^2}}\\\Rightarrow \Delta t'=25.52\ s$

∴ Time interval be if measured by an observer on the Enterprise would be 25.52 seconds

5 0

4 years ago

Clouds in our atmosphere cause us to see the different phases of the moon.

krok68 [10]

Answer:

False

Explanation:

:)

8 0

4 years ago

Read 2 more answers

A 5 kg bucket is lifted from the ground into the air by pulling in 10 meters of rope with linear density of 2 kg/m at a constant

iren [92.7K]

Answer:

Workdone W = 1465.1 J

Explanation:

The weight of the water = density × volume

weight of the water = 1000 kg/m³ × 100 cm³

weight of the water = 1000 kg/m³ × 0.0001 m³

weight of the water = 0.1 kg

weight of the bucket = 5 kg

weight of the rope = $2*10- 2x\\\\$

= $20- 2x$

Leakage = $\frac{0.1}{10} * x$

= $0.01 x$

Total weight = $5 + 20 - 2x - 0.01 x$

= $25 - 2.01 x$

Force = wg

Force = ( $25 - 2.01 x$ )g

Force = 9.8 ( $25 - 2.01 x$ )

Finally; the amount of work spent in lifting the bucket, rope, and water is calculated as follows:

$W = \int\limits^{10}_0 {(25-2.01 x)} \, 9.8 dx \\\\W = 9.8 (25x - \frac{2.01x^2}{2}})^{10}__0\\\\$

$W = 9.8 (25*10-2.01*50)\\\\W = 1465.1 \ \ J$

7 0

4 years ago