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Answer:
3360 N
Explanation:
In a first-class lever, the effort force and load force are on opposite sides of the fulcrum.
The lever is 5 m long. The load force is 1.50 m from the fulcrum, so the effort force must be 3.50 m from the fulcrum.
The torques are equal:
Fr = Fr
(1440 N) (3.5 m) = F (1.5 m)
F = 3360 N
<u>True</u> is your answer.
Hope this helps....
3.32µF and 1.64µF
Since, you haven't actually asked a question, I am going to make a guess on what the question is based upon the data provided. My educated guess is "What are the values of the two capacitors?"
The formula for the Capacitive reactance is
X = 1/(2*pi*f*C)
where
X = reactance
f = frequency
C = capactance
Let's solve for C
X = 1/(2*pi*f*C)
CX = 1/(2*pi*f)
C = 1/(2*pi*f*X)
Now with the capacitors in parallel, we have a reactance of:
I = V/X
IX = V
X = V/I
X = 12.3/0.56
X = 21.96428571
So the capacitance is:
C = 1/(2*pi*f*X)
C = 1/(2*pi*1460*21.96428571)
C = 4.96307x10^-6 = 4.96307 µF
And with the capacitors in series we have a reactance of:
X = V/I
X = 12.3/0.124
X = 99.19354839
So the capacitance is:
C = 1/(2*pi*f*X)
C = 1/(2*pi*1460*99.19354839)
C = 1.09896x10^-6 = 1.09896 µF
Now we can setup two equations with 2 unknowns.
4.96307 = x + y
1.09896 = 1/(1/x + 1/y)
y = 4.96307 - x
1.09896 = 1/(1/x + 1/(4.96307 - x))
1.09896 = 1/((4.96307 - x)/(x(4.96307 - x)) + x/(x(4.96307 - x)))
1.09896 = 1/(((4.96307 - x)+x)/(x(4.96307 - x)))
1.09896 = 1/(4.96307/(x(4.96307 - x)))
1.09896 = x(4.96307 - x)/4.96307
5.45422 = x(4.96307 - x)
5.45422 = 4.96307x - x^2
0 = 4.96307x - x^2 - 5.45422
0 = -x^2 + 4.96307x - 5.45422
We now have a quadratic equation. Use the quadratic formula to solve, getting roots of 3.320460477 and 1.642609523. You may notice that those 2 values add up to 4.96307. This is not coincidence. Those are the values of the two capacitors in µF. Rounding to 3 significant figures gives us 3.32µF and 1.64µF.
I believe the correct answer from the choices listed above is the third option. <span>The force exerted by the book on the table is equal to the force exerted by the table which is 4.0 N. The book does not move so it must be that the forces are balanced. Hope this answers the question.</span>