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Sholpan [36]
3 years ago
7

A 100 W electric heater (1 W = 1 J/s) operates for 11 min to heat the gas in a cylinder. At the same time, the gas expands from

1 L to 6 L against a constant external pressure of 3.527 atm. What is the change in internal energy of the gas? (1 L·atm = 0.1013 kJ)
Physics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

\Delta U = 64218.9 J

Explanation:

As we know that power of the heater is given as

P = 100 W

now the energy given by the heater for 11 min of time

E = P \times t

E = 100 \times 11 \times 60

E = 100\times 11 \times 60

E = 66000 J

now from 1st law of thermodynamics we know that

E = \Delta U + W

work done under constant pressure condition we have

W = P \Delta V

W = (3.527 \times 1.01 \times 10^5)(6 - 1) \times 10^{-3}

W = 1781.13 J

now from first equation we have

66000 = 1781.13 + \Delta U

\Delta U = 64218.9 J

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A cyclist travels at 15 m/s during a sprint finish. What is this speed in km/h
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54 km/hr

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3 years ago
A point charge of 9.00 × 10−9 C is located at the origin of a coordinate system. A positive charge of 3.00 × 10−9 C is brought i
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A point charge is located at the origin of a coordinate system. A positive charge is brought in from infinity to a point. The charges are at distance for given electrical potential energy is 3.34 x  10⁷ m.

<h3>What is electric potential energy?</h3>

The electric potential energy is the work done by a test charge to bring it from infinity to a particular location.

The electric potential energy is given by the relation,

V = kQ/r

where k = 9 x 10⁹ J.m/C ,Q = 3 x 10⁻⁹ C, V =8.09 × 10⁻⁷ J.

Substitute the values into the expression to get the distance between the charges.

8.09 × 10⁻⁷ =  9 x 10⁹ x  3 x 10⁻⁹ / r

r =3.34 x  10⁷ m

Thus, the distance between the charges will be 3.34 x  10⁷ m.

Learn more about  electric potential energy.

brainly.com/question/12645463

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8 0
2 years ago
Nervous tissue makes up most of the
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8 0
3 years ago
PLEASE HELP!!!!
defon

Answer:

v = 2.45 m/s

Explanation:

first we find the time taken during this motion by considering the vertical motion only and applying second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of cliff = 15 m

Vi = Initial Vertical Velocity = 0 m/s

t = time taken = ?

g = 9.8 m/s²

Therefore,

15 m = (0 m/s) t + (1/2)(9.8 m/s²)t²

t² = (15 m)/(4.9 m/s²)

t = √3.06 s²

t = 1.75 s

Now, we consider the horizontal motion. Since, we neglect air friction effects. Therefore, the horizontal motion has uniform velocity. Therefore,

s = vt

where,

s = horizontal distance covered = 4.3 m

v = original horizontal velocity = ?

Therefore,

4.3 m = v(1.75 s)

v = 4.3 m/1.75 s

<u>v = 2.45 m/s</u>

8 0
2 years ago
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