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xz_007 [3.2K]
3 years ago
15

two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 100 miles per

hour. The westbound train travels at 80 miles per hour. How long will it take for the two trains to be 252 miles apart? Do not do any rounding.
Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

1.4 hours

Step-by-step explanation:

you can write a system of equations to find the answer.

80t + 100t = 252

plug it into desmos to find the true value.

it is 1.4

the trains will be 252 miles apart after 1.4 hours.

if this helped, be sure to mark as brainliest :)

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3 years ago
Suppose that daily calorie consumption for american men follows a normal distribution with a mean of 2760 calories and a standar
lianna [129]

Answer:

38.11% probability that the mean of her sample will be between 2700 and 2800 calories

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 2760, \sigma = 500, n = 25, s = \frac{500}{\sqrt{25}} = 100

Find the probability that the mean of her sample will be between 2700 and 2800 calories

This is the pvalue of Z when X = 2800 subtracted by the pvalue of Z when X = 2700.

X = 2800

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2800 - 2760}{100}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 2700

Z = \frac{X - \mu}{s}

Z = \frac{2700 - 2760}{100}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

38.11% probability that the mean of her sample will be between 2700 and 2800 calories

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