Round 8.78911981582 to the nearest millionth

Mathematics

1 answer:

Aliun [14]3 years ago

8 0

Answer:

8.789120

(you have to include the zero, or else the answer would no longer be the nearest millionth! and you would be marked wrong)

You might be interested in

Show that if f(n) is O(g(n)) and d(n) is O(h(n)) then f(n) + d(n) is O(g(n) + h(n)).

GaryK [48]

$f(n)\in\mathcal O(g(n))$ is to say

$|f(n)|\le M_1|g(n)|$

for all $n$ beyond some fixed $n_1$ .

Similarly, $d(n)\in\mathcal O(h(n))$ is to say

$|d(n)|\le M_2|h(n)|$

for all $n\ge n_2$ .

From this we can gather that

$|f(n)+d(n)|\le|f(n)|+|d(n)|\le M_1|g(n)|+M_2|h(n)|\le M(|g(n)|+|h(n)|)$

where $M$ is the larger of the two values $M_1$ and $M_2$ , or $M=\max\{M_1,M_2\}$ . Then the last term is bounded above by

$M(|g(n)|+|h(n)|)\le2M\max\{|g(n)|,|h(n)|\}$

from which it follows that

$f(n)+d(n)\in\mathcal O(\max\{g(n),h(n)\})$

3 0

3 years ago

A bookstore contains 75972 books,divided in to three sections. The science represents 1/3 of the total books. The remaining book

S_A_V [24]

Answer:

12,662 books

Step-by-step explanation:

Total number of books = 75,972

No. of science books = ⅓ of 75,972 = ⅓*75,972 = 25,324 books.

No. of business books = 75% of the remaining books = 75% of (75,972 - 25,324)

= $\frac{75}{100}*50,648 = 37,986$