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3 years ago

Given that tan2theta=3/8,what is the value of sec theta

1 answer:

4 0

There's an identity

sec^2 x = 1 + tan^2 x

so here we have

sec^2 theta = 1 + (3/8)^2 = 73/64

sec theta = sqrt 73 / 8 or 1.068 to nearest thousandth

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Only thing I need to know is what to do for the x on y = x + 3 and y = x

Ronch [10]

Answer:

Think of y = mx + b,

With y = x + 3, m = 1 so the slope is one, and b = 3 which is the y-intercept, so plot the point (0,3) on the y-axis.

To find the next point to plot go up 1 and over to the right 1 because slope is rise over run.

With y = x, the slope is still 1, but there is no y-intercept, so you plot the point (0,0), and to find the next point on that line, go up 1 and over the right 1 because m=1

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3 years ago

When the integer n is squared, the result is less than 150. What is the sum of all possible values of n?

Rom4ik [11]

Answer = 0

n can have possible values from (-12) to 12
-12 <= n < 12

(-12) + (-11)+(-10)......+10+11+12=0

5 0

3 years ago

I need help on this equation 6s-10=s

dusya [7]

The equation:    6s - 10 = s

Add 10 to each side:    6s    = s + 10

Subtract 's' from each side: 5s    = 10

Divide each side by 5 : s = 2

3 0

3 years ago

If triangle abc is similar to triangle edc find the value of x

svetoff [14.1K]

Answer:

x = 15

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{BC}{DC}$ = $\frac{AC}{EC}$ , substitute values

$\frac{3x-5}{32}$ = $\frac{5x-5}{56}$ ( cross- multiply )

56(3x - 5) = 32(5x - 5) ← distribute and simplify both sides

168x - 280 = 160x - 160 ( subtract 160x from both sides )

8x - 280 = - 160 ( add 280 to both sides )

8x = 120 ( divide both sides by 8 )

x = 15

4 0

3 years ago

The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va

Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

$d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore$

4 0

3 years ago