Answer:
hihjjjkkcjkbcgukn c
Step-by-step explanation:
v mkkjljjj
Okay so $14,000 is the equivalent of 6/5ths
so divide $14,000 by 6= $2333.3r
you need 5/5
so $2333.3r x 5 = $11666.67
this is the original price
Answer:
r= 42.48 and d=84.96
Step-by-step explanation:
too slow to type solution, gogogo answer your thing dude!
The correct question is:
Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)
Answer:
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
Step-by-step explanation:
We need to verify that
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
We differentiate
x = c1e^(-t) + c2e^(3t)
twice in succession, and substitute the values of x, x', and x'' into the differential equation
x''- 2x' - 3x = 0
and see if it is satisfied.
Let us do that.
x = c1e^(-t) + c2e^(3t)
x' = -c1e^(-t) + 3c2e^(3t)
x'' = c1e^(-t) + 9c2e^(3t)
Now,
x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]
= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)
= 0
Therefore, the differential equation is satisfied, and hence, x is a solution.
Answer:
<em>84%</em><em> of the wage earners earn less than $14,000 each. </em>
Step-by-step explanation:
The Empirical Rule (68-95-99.7%)-
According to this around 95% of the data will fall within two standard deviations of the mean.
As the bell curve is symmetrical, so the remaining 5% will be divided into 2 equal parts. So 2.5% will be above 2 standard deviation and 2.5% will be below 2 standard deviation.
As it is given that, the top 2.5% of the wage earners earn $18,000 or more, so 18,000 is 2 standard deviation away from the mean 10,000.
i.e 
We know that,
where,
X = raw score = 14,000
μ = 10,000
σ = 4,000
Putting the values,
Now, calculating the value from the z score table,
As the probability at 
is the area below that, so 84% of the wage earners earn less than $14,000 each.
