Answer:
You need to find the volume in two parts then add them together, think of the shed as box and a rectangular prism.
Volumebox=length x width x height
Volumeprism=1/2 x base of triangle x height of triangle x length
Hope this helps,
HARIPREETA
Answer:

Step-by-step explanation:
From the question we are told that:
Percentage of audience in first concert 
Percentage of audience in second concert 
Percentage of audience in third concert 
Audience Percentage at at-least one concert 
Percentage of audience at first & second concert 
Percentage of audience in first & third concert 
Percentage of audience in second & third concert 
Generally the equation for probability of attending all concerts
is mathematically given by




Therefore the probability that a randomly selected audient attended all the concerts

Answer:
ur sti]upid
Step-by-step explanation:
get a bucket and a mop thats a wap