The equation of the function given as (x)= 5 * 2^x is an exponential function
<h3>How to determine the function type?</h3>
The equation of the function is given as
f(x)= 5 * 2^x
An exponential function is represented as
f(x) = a * b^x
Where
Initial value = a
Rate = b
This means that
a = 5
b = 2
Hence, the equation of the function given as (x)= 5 * 2^x is an exponential function
Read more about exponential function at
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Answer:
No
Step-by-step explanation:
Laura painted her room with pink paint that was made by mixing paint at a ratio of 5 parts white paint to 2 parts red paint.
Suppose Laura has 15 parts of white paint. This is thrice the amount Laura needs (because
), so she has to have

parts of red paint.
Hence, if Laura combines 15 parts white and 3 parts red paint, then she will not create the same shade of pink as she used.
92% just divide the numerator by the denominator
Answer:
1. 1343 years
2. 9 hours
3. 39 years
Step-by-step explanation:
1. Given, half-life of carbon = 5730 years.
∴ λ = 0.693/half-life of carbon = 0.693/5730 = 0.000121
If N₀ = 100 then N = 85
Formula:- N = N₀*e^(-λt)
∴ 85 = 100 * e^(-0.000121t)
∴㏑(-0.85)=-0.000121t
∴ t = 1343 years
2. Given half-life of aspirin = 12 hours
λ = 0.693/12 = 0.5775
Also N₀ = 100 then 70 will disintegrate and N = 30 will remain disintegrated.
∴ 70 = 100 *e^(-0.05775t)
0.70 = e^(-0.05775t)
㏑(0.70) = -0.05775t
∴ t = 9 hours
3. The population of the birds as as A=A₀*e^(kt)
Given that the population of birds fell from 1400 from 1000, We are asked how much time it will take for the population to drop below 100, let that be x years.
The population is 1400 when f = 0, And it is 1000 when f = 5
We can write the following equation :
1400 = 1000e^(5t).
∴1400/1000 = e^(5k)
∴ k = ㏑(1.4)/5
We need to find x such that 1400/100 = e^(xk)
14 = e^(xk)
∴ x = 39 years
Answer:
No
Step-by-step explanation:
She is a way higher level of math and the math she is in is not algebra. However we can assume that the regular algebra students will do worse as statistics is a lot harder than algebra.