Answer:
Yes.
Step-by-step explanation:
Answer:
So, L'Hospital's Rule tells us that if we have an indeterminate form 0/0 or ∞/∞ all we need to do is differentiate the numerator and differentiate the denominator and then take the limit. (Brainliest? :3)
Step-by-step explanation:
Answer:
is one to one mapping, it is not onto mapping
Step-by-step explanation:
f₁(x) is one to one mapping
Let 
f₁(x) = f₁(y):
x₁³ = y₁³
f₁(x) is not onto mapping
Example: If f₁(x) = 7,
x₁³ = 7
![x_{1} = \sqrt[3]{7}](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%20%5Csqrt%5B3%5D%7B7%7D)
x₁ is not an element of Z
is one to one mapping, it is not onto mapping
Lets compare both equations so we can explain the reason for it, and see it clearly:
<span>y1 = 5x + 1
</span><span>y2 = 4x + 2
y1 > y2
</span>5x + 1 > 4x + <span>2
</span>To see why that happens we need to solve for x:
5x - 4x > 2 - 1
x > 1
Therefore, the first equation is greater than the second for values of x > 1
