All categories

3 years ago

Can someone please help me it's due today

Mathematics

2 answers:

bija089 [108]3 years ago

4 0

please see photo attached

yaroslaw [1]3 years ago

3 0

Answer:

Step-by-step explanation:

Make 12 into a fraction : 12/1

Then , using division with fractions , flip the 3/5 and multiply 12/1 and 5/3 .

The equation will look like this :

12/1 x 5/3

So 12 x 5 = 60 and 1 x 3 = 3 , making the fraction 60/3

That then simplifies to 20

You might be interested in

Jessica bought a $30 outfit for $17. What percent discount did she receive?

mihalych1998 [28]

<h2>Answer:</h2>

Around 57%

<h3><u>Step-by-step explanation:</u></h3>

17 / 30 = .56666666...

Move two decimal places to the left;

56.66666...

<em>Estimate:</em> 57%

8 0

3 years ago

Read 2 more answers

Will Give brainliest!

Varvara68 [4.7K]

Answer:

It’s been a while.... I was send somewhere bad....

How are you

It’s chris Steven cummmings

And I’m sorry so sorry

7 0

3 years ago

Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin

NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

Assuming that $\bar X =5.5$ and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=1086-1=1085$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that $t_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139$

$5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861$

So on this case the 95% confidence interval would be given by (5.139;5.861) We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0

3 years ago

An artist pours 60 gallons of paint equally into 8 containers how much paint is in each container?

uranmaximum [27]

Answer:

7.5

Step-by-step explanation:

cause you can divide the 60 with the 8

4 0

3 years ago

Read 2 more answers

For a certain online store, the distribution of number per hour is approximately normal with mean 1200 purchases and standard de

Advocard [28]

Answer: 16%

Step-by-step explanation:

When we have a normal distribution, the 100% of our sample will be placed in a "gaussian bell".

Where the middle of this bell coincides with the mean.

The mean, in this case, is 1200, and the standard deviation is 200.

In the image below you can see that between the points.

Mean + standard deviation and the end of the graph, we have:

13.5% + 2.35% + 0.15% = 16%

And particularly, if we want to know the percentage that exceed 1400, will be the same percentage above the mean plus the standard deviation.

mean = 1200

SD = 200

mean + standard deviation = 1200 + 200 = 1400.

Then the percentage that exceeds 1400 is equal to the percentage that we found above, then the correct option is C: 16%

5 0

3 years ago