L = 20 and W = 15
Explanation:
Let's review what is known about the rectangle in question - the area is 300 cm squared and the ratio of the Length to the Width (which I'll shorten to L and W) is 4:3.
Let's start with the ratio. We know that they are related to each other - 4 of a basic unit of length for L and 3 of that same basic unit of length for W. So we can say that
L =
4
x
and W =
3
x
We also know from the formula for the area of a rectangle that LW = Area of the rectangle. Substituting in the terms with the x's in them gives us
(
4
x
)
(
3
x
)
=
300
so let's solve for x:
12
x
2
=
300
x
2
=
300
12
=
25
x
=
√
25
=
5
(ignoring the negative root since that makes no sense in this application)
Substituting x back into our equations for L and W, we get
L =
4
(
5
)
=
20
and W =
3
(
5
)
=
15
Checking our work - there is a ratio of L:W of 4:3. And LW =
20
⋅
15
=
300
Hope this is what you meant
The picture in the attached figure
let
AB=x
we know that
perimeter of the figure=10*x
perimeter=42.5 cm
so
42.5=10*x
x=42.5/10
x=4.25 cm
area of the figure=area of rectangle +area of square
area of rectangle=4.25*(4.25*3)----> 54.1875 cm²
area of square=4.25²----> 18.0625 cm²
area of the figure=54.1875+18.0625-----> 72.25 cm²
the answer is72.25 cm²
Answer:
It is both a relation and a function.
Step-by-step explanation:
Keith collected the names and ages of all of his classmates and organized them in the ordered pair (name, age).
Here, if we consider the name as the input and age is the output, then each and every different input there is a single output.
Because a single person can not have more than one age.
Therefore, it is both a relation and a function. (Answer)
The answer is four
See my handwritten problem worked out in attached pic
Answer:
See Explanation
Step-by-step explanation:
Given


Required
Determine the true statement about b
The question is incomplete as options are not given. However, a general explanation is as follows:
Rewrite 

When a = 0

When a = 1

This means that:
For 
Then 
<em>This means that: b is a number between 0 and 8</em>