Answer:
he has to ride 6 miles 1 once day
Answer:
(x,y,z)=( -2, -1 ,5)
Step-by-step explanation:
9x+2y-27z=-155 (1)
-11x-y+37z=208 (2)
19x+6y-52z=-304 (3)
(1) *3 ;(2) *6 ;(3)*1, you have
27x+6y-81z=-465 (1)
-66x-6y+222z=1248 (2)
19z+6y-52z=-304 (3)
(1) +(2), you have
-39x+141z= 783 (4)
(4) /3, you have
-13x +47z=261 (4)
(2) +(3), you have
-47x+170z=944 (5)
From ( 4) and (5), you have equations
-13x +47z=261 (4)
-47x+170z=944 (5)
(4)*(-47); (5)*13, you have
611x-2209z=-12,267 (4)
-611x+2210z=12,272 (5)
(4)+(5), you have
z=5
Replace z=5 in (4), you have
611x- 2209*5=-12,267
611x- 11,045 =-12,267
611x=-1222
x= -2
Replace x=-2, z=5 in (1) , you have
9*(-2) +2y -27*5=-155
-18+2y-135=-155
-18+2y=-20
2y=-2
y=-1
Result (x,y,z)=( -2, -1 ,5)
The value of 4 in 2402 is hundred and in the value in 64513 is thousand and that is your answer
Answer:
C
Hope that helps!
Step-by-step explanation:
<h3>
Answer:</h3>
- 32 kg of 30% copper
- 48 kg of 55% copper
<h3>
Step-by-step explanation:</h3>
Let x represent the mass of 55% copper alloy that is to be used in the mix. Then 80-x is the mass of 30% copper alloy to be used. The total amount of copper in the mix is then ...
... 0.55x + 0.30(80-x) = 0.45·80
... 0.25x = 12 . . . . . . simplify, subtract 24
... x = 48 . . . . . . . . . divide by the coefficient of x
... 80-x = 32 . . . . . . the mass of 30% copper alloy required
The metalworker should combine 32 kg of 30% copper alloy with 48 kg of 55% copper alloy to make 80 kg of 45% copper alloy.
