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4 years ago

Which residual plots indicate that the original data set has a linear relationship? Check all that apply

Mathematics

2 answers:

Leto [7]4 years ago

8 0

Answer:

Step-by-step explanation:

Bro, where's the photo?

Amanda [17]4 years ago

4 0

Answer: A, B and E

Step-by-step explanation:

A residual values should be equally and randomly spaced around the horizontal axis. If the plot looks like any of the images in C and D, then the data set is probably not a good fit for regression. A non-linear pattern is more appropriate.

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PLS HURRY!!!

WITCHER [35]

Answer:

Right.

Step-by-step explanation:

The answer is right on edge2020 I just took the test.

4 0

3 years ago

Read 2 more answers

Solve <img src="https://tex.z-dn.net/?f=2%20cosx%3D4cosx%20sin%5E2x" id="TexFormula1" title="2 cosx=4cosx sin^2x" alt="2 cosx=4c

Ilia_Sergeevich [38]

There are four solutions for the <em>trigonometric</em> equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i, $i \in \mathbb{N}_{O}$ .

<h3>How to solve a trigonometric equation</h3>

In this problem we must simplify the <em>trigonometric</em> equation by both <em>algebraic</em> and <em>trigonometric</em> means and clear the variable x:

2 · cos x = 4 · cos x · sin² x

2 · sin² x = 1

sin² x = 1/2

sin x = ± √2 /2

There are several solutions:

x₁ = π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

x₂ = 3π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

x₃ = 5π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

x₄ = 7π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

To learn more on trigonometric equations: brainly.com/question/27821667

#SPJ1

4 0

2 years ago

Solve for y.<br> 8+4y= -8

Andrew [12]

Answer:

-4

Step-by-step explanation:

8+4y= -8

4y= -8 -8

4y= -16

divide both sides by the coeffient of the variable. in this case divide both sides by 4

y=-4

7 0

3 years ago

Read 2 more answers

True or false two points that map together never coincide

azamat

False.

2 points that map the borders of a city could meet up at a ridge or valley.

7 0

3 years ago

In a research lab, a cell biologist is growing a strain of bacteria under two different conditions. Culture A had an initial pop

zhannawk [14.2K]

Answer:

They will have the same population after 6 hours

Step-by-step explanation:

The general exponential equation format for this is;

P = P_o(e^(kt))

For Culture A, we are told that it had an initial population of 200 and doubles every hour.

Thus;

After 1 hour, P = 400

After 2 hours, P = 800

After 3 hours, P = 1600

Thus;

At t = 1, we have;

400 = 200(e^(k × 1))

400/200 = e^(k)

e^(k) = 2 - - - (eq 1)

At t = 2, we have;

800 = 200(e^(k × 2))

800/200 = e^(2k)

e^(2k) = 4 - - - (eq 2)

To find k, let's divide eq 1 by eq 2.

(e^(2k))/e^(k) = 4/2

e^(2k - k) = 2

e^(k) = 2

k = In 2

k = 0.6931

Thus;

P = 200e^(0.6931t)

For Culture B, we are told that it had an initial population of 819200 but has been contaminated. Its population is now decreasing by half every hour.

Thus;

After 1 hour, P = 409600

After 2 hours, P = 204800

After 3 hours, P = 102400

Thus;

At t = 1, we have;

409600 = 819200(e^(k × 1))

409600/819200 = e^(k)

e^(k) = 0.5 - - - (eq 1)

At t = 2, we have;

204800 = 819200(e^(k × 2))

204800/819200 = e^(2k)

e^(2k) = 0.25 - - - (eq 2)

To find k, let's divide eq 1 by eq 2.

(e^(2k))/e^(k) = 0.25/0.5

e^(k) = 0.5

k = In 0.5

k = -0.6931

Thus;

P = 819200(e^(-0.6931t))

We want to find the time when the 2 cultures will have the same population. Thus;

200e^(0.6931t) = 819200(e^(-0.6931t))

Arranging, we have;

(e^(0.6931t))/(e^(-0.6931t)) = 819200/200

e^(0.6931t - (-0.6931t) = 4096

e^(1.3862t) = 4096

1.3862t = In 4096

1.3862t = 8.3178

t = 8.3178/1.3862

t ≈ 6 hours

3 0

4 years ago