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MissTica
3 years ago
15

HELP ASAP I don’t get it

Mathematics
2 answers:
Tamiku [17]3 years ago
7 0

Answer:

-11/5

Step-by-step explanation:

In order to solve it u should open the mixed fraction ,i.e,

11/7÷-15/21

=11/7×-21/15

Cutting,

ans=-11/5

Mark me the brainliest

miv72 [106K]3 years ago
5 0

Answer:

Fraction: -11/5

Decimal form: -2.2

Mixed number form: -2 1/5

Step-by-step explanation:

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Convert 3.2 repenting decimal into a fraction
Olenka [21]
x =3.\bar{2}\\10x = 32.\bar{2}\\\\ 10x - x = 32.\bar{2} - 3.\bar{2}\\9x = 29\\x = \frac{29}{9}\\\\\\ \boxed{\bf{\frac{32}{9} = 3.\bar{2}}}
7 0
3 years ago
Thanks i got it right
denpristay [2]

Answer:

got what right?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which is the height of the triangle?<br> ( PIC IS PROVIDE PLS HELP ME)
zysi [14]
<h3>Answer: 80 meters</h3>

This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).

So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.

a^2 + b^2 = c^2

x^2 + (60)^2 = (100)^2

x^2 + 3600 = 10000

x^2 = 10000 - 3600

x^2 = 6400

x = sqrt(6400)

x = 80

Each smaller right triangle has side lengths of 60, 80, 100

Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.

5 0
3 years ago
Read 2 more answers
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
Listed below are the summary statistics from samples of strontium-90 in baby teeth obtained from twelve Pennsylvania residents a
qaws [65]

Answer:

9.72

Step-by-step explanation:

s1 = 10.6383 ; s2 = 5.21289

x1 = 147.583 ; x2 = 136.417

n1 = 12 ; n2 = 12

df1 = n1 - 1 = 12 - 1 = 11

df2 = n2 - 1 = 12 - 1 = 11

The test statistic :

(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]

Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)

Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926

Test statistic, T* :

(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))

11.166 / √(7.926 * (1/6)

11.166 / √1.321

11.166 / 1.1493476

T* = 9.7150766

Test statistic = 9.72

5 0
3 years ago
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