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MissTica
3 years ago
10

the ages of two friends Sunaina and Tanish are differ by 2 years sunaina's father is twice as old as Sunaina and Tanisha is twic

e as old as his brother Shiva The ages of sunaina's father and Shiva differ by 40 years
Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

Let S represent Sunaina's age.

Let T represent Tanish's age.

So 2S - T/2 = 40, 4S - T = 80.

Either S - T = 2 or T - S = 2. Let's try both cases.

Either 3S = 78 or 3S = 82.

Since 82 is not a multiple of 3, S = 26.

So Sunaina is 26 years old and Tanish is 24 years old.

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480 in.

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En una sociedad participan 5 socios, colocando todos capitales iguales, lo unico que el primer socio estuvo 1 año y medio, el se
Mashutka [201]

Answer:

Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

Step-by-step explanation:

Dado que en una sociedad participan 5 socios, colocando todos capitales iguales, lo único que el primer socio estuvo 1 año y medio, el segundo 9 meses, el tercero 5 meses mas que el primero, el cuarto 1 año 7 meses y el quinto 2 años, para determinar cuánto le toca a cada socio de una utilidad de Q. 55,230.00 se deben realizar los siguientes cálculos:

Socio 1 = 1.5 años

Socio 2 = 0.75 años

Socio 3 = 1.916 años

Socio 4 = 1.583 años

Socio 5 = 2 años

Total = 1.5 + 0.75 + 1.916 + 1.583 + 2 = 7.75

Socio 1 =

7.75 = 100

1.50 = X

1.50 x 100 / 7.75 = X

19.35 = X

55,230 x 0.1935 = 10,690

Socio 2 =

7.75 = 100

0.75 = X

0.75 x 100 / 7.75 = X

9.68 = X

55,230 x 0.0968 = 5,345

Socio 3 =

7.75 = 100

1.916 = X

1.916 x 100 / 7.75 = X

24.72 = X

55,230 x 0.2472 = 13,655

Socio 4 =

7.75 = 100

1.583 = X

1.583 x 100 / 7.75 = X

20.43 = X

55,230 x 0.2043 = 11,285

Socio 5 =

7.75 = 100

2 = X

2 x 100 / 7.75 = X

25.81 = X

55,230 x 0.2581 = 14,255

Por lo tanto, Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

5 0
2 years ago
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