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kvv77 [185]
3 years ago
12

If G = 70° and J = 40°, then GH ___ HJ. Choose the correct symbol to put in the blank.

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

Answer:

GH < HJ

Step-by-step explanation:

We are given that

\angle G=70^{\circ}

\angle J=40^{\circ}

We have to fill the correct symbol in the blank space.

Greater angle and greater side theorem: It states that when

\angle A>\angle B

Then, Opposite side to angle  A > opposite side to angle B.

When Opposite side to angle  A > opposite side to angle  B

Then, \angle A >\angle B

Side opposite to angle J=GH

Side opposite to angle G=HJ

Using the above theorem,

\angle G >\angle J

Then, HJ >GH

Hence, GH < HJ

Novosadov [1.4K]3 years ago
7 0

Answer:

GH > HJ

The correct symbol is " >" (greater)

Step-by-step explanation:

we know that

In the triangle GHJ applying the law of sines

\frac{GH}{sin(J)}=\frac{HJ}{sin(G)}

substitute the given values

\frac{GH}{sin(40\°)}=\frac{HJ}{sin(70\°)}

Isolate GH

GH=\frac{HJ}{sin(70\°)}(sin(40\°))

GH=1.46(HJ)

therefore

GH > HJ

The correct symbol is " >" (greater)

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Triangles O N M and S R Q are shown. Angles O N M and S R Q are congruent. The length of side N M is 10 and the length of side S
valina [46]

Answer:

Option C.

Step-by-step explanation:

In △ONM and △SRQ,

\angle ONM\cong \angle SRQ

NM=10

SR=20

NO=8

QR=x

We need to find the value of x that will make △ONM similar to △SRQ by the SAS similarity theorem.

According to SAS similarity theorem, two triangle are similar if two corresponding sides in both triangles are proportional and the included angle in both are congruent.

It is given that \angle ONM\cong \angle SRQ. So, both triangles are similar by SAS if

\dfrac{NO}{NM}=\dfrac{SR}{QR}

Substitute the given values.

\dfrac{8}{10}=\dfrac{20}{x}

8\times x=20\times 10

8x=200

Divide both sides by 8.

x=\dfrac{200}{8}

x=25

Therefore, the correct option is C.

7 0
3 years ago
Read 2 more answers
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
Will give brainlist, help please
Minchanka [31]

Answer:

Step-by-step explanation:

It is blurry sorry man

3 0
3 years ago
Establece el producto cartesiano;representa en diagrama sagital y plano cartesiano M={a,b,c} N={4,8,12} ayuda​
Elza [17]

Answer:

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Step-by-step explanation:

6 0
2 years ago
800 hundred 2 hundred standord form
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800 = 8 x 10^2 in standard form
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