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3 years ago

What is the answer? Please help! As quick as you can!

Mathematics

2 answers:

Art [367]3 years ago

6 0

The solution is the last one. The answer is 7

Vikentia [17]3 years ago

5 0

Answer:

x=7 is the only answer

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Producing a musical costs $88,000 plus $5900 per performance. one sold out performance earns $7500 in revenue. If every performa

yan [13]

X = # of perfomances

y = total amount of money

Income: y = 7500x

Expense: y = 5900x + 88000

Substitution:

7500x = 5900x + 88000

1600x = 88000

x = 55

y = 7500(55) = $412,500

55 performances are needed to break-even.

5 0

3 years ago

During a school event, Noah is selling pizza at the food stand for $1.25 per slice.

Eddi Din [679]

Answer:

1. When he sold 20 slices of pizza at $1.25 each, he made $20

When he sold 50 slices of pizza at $1.25 each, he made $62.5

2. 96 slices of pizza. You would get that by dividing 120 by 1.25, as he needs to make $120, and each slice costs $1.25

7 0

3 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

3 years ago

Watch help video

ollegr [7]

Answer: 15309

hope this helps, the nth term calulation is (7/3) times 3^n

6 0

2 years ago

I need help! If this correct 22?

Gala2k [10]

Answer: Yes its correct

6 0

1 year ago