Answer:
W = X in.
L = (3x - 6) in.
A = L*W = (3x-6)X = 45,
3x^2 - 6x = 45
3x(x-2) = 45,
x(x-2) = 15,
x^2 - 2x - 15 = 0
(x-5)(x+3) = 0,
x-5 = 0,
x = 5 in.
x+3 = 0,
x = -3.
Solution Set: x = 5, and x = -3.
Select + value of X:
x = 5
W = x = 5 in.
L = 3x-6 = 3*5 - 6 = 9 in.
Step-by-step explanation:
Answer:
1.5 seconds
Step-by-step explanation:
h=-16t² – 16t+ 60
When the rock enter the water, the height is 0. ... h=0
0 = -16t² – 16t+ 60 = -4 * (4t² - 4t +15) = -4* (2t - 3) (2t +5)
2t-3=0 or 2t+5 = 0
t = 3/2 or t = -5/2 (time can't be negative)
t = 3/2 or 1.5
Answer:
15 inches
Step-by-step explanation:
We have that,
Length of the photo = 4 inches and Width of the photo = 6 inches
Also, the width of the image on the calendar = 10 inches
Let, the length on the image of the calendar = x inches.
Since, the ratio of the photo and its image will remain same, we get,

i.e. 
i.e. x = 15
Hence, the length of the image of the photo on the calendar is 15 inches.
To solve this, since you know that h(x) is 11 and that it also equals -4x+3, you set them equal to one another which would look like this: 11=-4x+3.
Then, to solve for x, which is what I am assuming the question is asking, you would subtract 3 from both sides to isolate -4x, which would result in this:
-4x=8
Now, to solve for x, divide both sides by -4, and you get your answer which is x=-2