Answer:

Step-by-step explanation:
The nth term for the geometric sequence is given by:

where,
is the first term
r is the common ratio
n is the number of terms.
As per the statement:
For the geometric sequence of
and r=2
We have to find 
for n = 5;

Substitute the given values we have;

⇒
Therefore, the value of
is, 32
Answer:

Step-by-step explanation:
The last one is also the answer
Using the rational exponet rule,
![\sqrt[n]{ {x}^{m} } = x {}^{ \frac{m}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B%20%7Bx%7D%5E%7Bm%7D%20%7D%20%20%3D%20x%20%7B%7D%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20)
Using this number,

40 is the base so it will stay same. Remember this is a square root sign so our nth root is 2 so our denominator if the rational exponet is 2.

so our numerator is 1 so

Answer:
Step-by-step explanation:
Here you go mate
Step 1
3x(1.05) Equation/Question
Step 2
3x(1.05) Simplify
3x(1.05)
Step 3
3x(1.05) Multiply them
Answer
3.15x
Hope this helps
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°