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mihalych1998 [28]
3 years ago
5

Please help this is due tomorrow!!

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
4 0

Answer:

x+y=30 and x-y=8. Angel is 11 and Alex is 19

Step-by-step explanation:

30÷2=15

8÷2=4

15-4=11

15+4=19

19+11=30

Nikitich [7]3 years ago
3 0
Angel is 8 years old and Alex is 30 years old x-y=30
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Two adjacent angles of a rhombus as in the ratio 2:3. Eind all the a angles of the rombus​
Tomtit [17]

Answer:

Let the adjacent angles of the rhombus be 2x and 3x. We know that the sum of the measures of the adjacent angles is equal to 180°. AD = DC = 3 × 36° = 108°. Hence , the angles of the rhombus are 72° , 108° , 72° and 108°.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Hippalectryon
horrorfan [7]
Since the stadium is 6 mi from the practice field which is itself 1 mi from the house, it can either be (1+6)=7 mi North or (1-6)=-5 -> 5 mi South depending on the North/South direction.

the answer is thus A
7 0
2 years ago
WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0
3 years ago
Find each missing lengths to the nearest tenth PLEASE HELP
alisha [4.7K]

Answer:

For #1, 8.9.

Step-by-step explanation:

I can attempt to answer it, but I can't promise anything.

Alright, so, the equation for this should be A²+B²=C²

C is usually the longer side, which for you is the side that is missing.

Let's try the first one. If what I see is right, the 2 sides are 4 and 8. A is 8 and B is 4.

That means that the equation would be 8²+4²=C²

That would be 64+16=80

The equation is now 80= c²

The opposite of "to the power of 2" is a square root. So, now you're going to find the square root of 80, which is 8.9 to the nearest tenth.

So, for the first question, the answer should be 8.9

I hope this helps you solve the rest.

6 0
3 years ago
Find the endpoint of the line segment
blondinia [14]

Answer:

(29,-13)

Step-by-step explanation:

You can tackle this for x and y coordinate separately.

For x, the line starts at -9 and is halfway at 10. The distance between -9 and 10 is 19 so it has another 19 to go, which puts the endpoint at 10+19=29.

Same for y: from 7 to -3 is 10 down, another 10 to go, puts you at -13.

Formula: x,y of midpoint is ((x1+x2)/2, (y1+y2)/2)

3 0
3 years ago
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