Answer:
The graph
has two zeros namely 3 and 1.
Step-by-step explanation:
Consider the given equation of graph
According to the Fundamental Theorem of Algebra
For a given polynomial of degree n can have a maximum of n roots.
Thus, for the given equation
the degree of polynomial is 2 , thus the function can have maximum of 2 roots.
We know at roots the value of function is 0 that is f(x) = 0,
Substitute f(x) = 0 , we get, 
This is a quadratic equation, 
We first solve it manually and then check by plotting graph.
Quadratic equation can be solved using middle term splitting method,
here, -4x can be written as -x-3x,



Using zero product property, 
or 
or 
Thus, the two zero of f(x) are 3 and 1.
We can also see on graph attached below that the graph
has two zeros namely 3 and 1.