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Andru [333]
2 years ago
14

Find four consecutive integers such that 8 times the sum of the first and the third is 40

Mathematics
1 answer:
jolli1 [7]2 years ago
7 0
The consecutive integers are 9,10,11,12.
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2,300+-2,500+3,300+-2,600+6,250
Lorico [155]
1 Simplify

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2 Simplify

<span><span>6,750

I hope this helps. 

Have a awesome day. :)

</span><span>
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Jonah is the one that is correct because 1/6th of 1248 is 208. Then you add 1248 and 208 which is 1456 which is the correct answers

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Can someone help me please?! I'll give brainlest for correct answer​
mojhsa [17]

1.) The answers:

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2 years ago
How do you factor 6x² +7x-3? Please show the steps!
Gnesinka [82]
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Hope this might help u

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