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Andru [333]
3 years ago
14

Find four consecutive integers such that 8 times the sum of the first and the third is 40

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0
The consecutive integers are 9,10,11,12.
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satela [25.4K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Solve by substitution y=9x-19 6x-2y=26
sineoko [7]

Answer:

Step-by-step explanation:

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4 0
3 years ago
Graph the equation below by plotting the y-intercept and a second point on the line. <br> Y=3/2x-5
nikitadnepr [17]

Answer:

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8 0
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I need ur smart brain power!!!!!
Andrej [43]

Answer:

y = -2x -3

Step-by-step explanation:

I love slope-intercept form! lol

y =mx +b

so we have 2 points given: (-1,5) and (4,-5)

to find the SLOPE of the slope-intercept form, we need to subtract and divide

(-5-5)/(4+1)

-10/5= -2 which is our slope

now! lets translate this info into point slope form. y - y1 = m (x - x1)

(-1,5) and we kno the slope is -2.

y - 5 = -2 (x - (-1))

y-5 = -2(x + 1)

y-5 = -2x -2

add five

y = -2x -3    we are back to slope intercept form! YAY!

3 0
3 years ago
Pls help 25 divided by 1.675 with remainder
raketka [301]
The answer is 14.9253 i searched it up so there isn’t a remainder but that’s the decimal so..
4 0
3 years ago
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