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Aleonysh [2.5K]
3 years ago
10

The ratio of the side length of Square A to the side length of Square B is 11:9 the area of Square A is 448 cm^2. What is the pe

rimeter of square B?
Mathematics
1 answer:
QveST [7]3 years ago
5 0

\text{Square}A\sim\text{Square}B\ in\ scale\ k,\ then\ \text{Area}A:\text{Area}B=k^2\\\\a,\ b-\text{the lenght of the sides of the squares}\\\\a:b=11:9\to A_A:A_B=\left(\dfrac{11}{9}\right)^2\\\\A_A=448\ cm^2\\\\\text{Substitute}\\\\\dfrac{448}{A_B}=\left(\dfrac{11}{9}\right)^2\\\\\dfrac{448}{A_B}=\dfrac{121}{81}\qquad|\text{cross multiply}\\\\121A_B=(448)(81)\qquad|:121\\\\A_B=\dfrac{(448)(81)}{121}\\\\A_B=b^2\to b^2=\dfrac{(448)(81)}{121}\to b=\sqrt{\dfrac{(448)(81)}{121}}

b=\sqrt{\dfrac{(64)(81)(7)}{121}}\\\\b=\dfrac{\sqrt{(64)(81)(7)}}{\sqrt{121}}\\\\b=\dfrac{\sqrt{64}\cdot\sqrt{81}\cdot\sqrt7}{11}\\\\b=\dfrac{(8)(9)\sqrt7}{11}\\\\b=\dfrac{72\sqrt7}{11}\\\\\text{The perimeter is}\ P_B=4b\to P_B=4\cdot\dfrac{72\sqrt7}{11}=\dfrac{288\sqty7}{11}\ cm


Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}

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