$20,000 is between $15,000 and $49,999, so we'll use the interest rate of 6.5% (see row 3)
r = 6.5% = 6.5/100 = 0.065
We'll use the decimal form of the interest rate as it is most common for financial math problems.
P = 20,000 is the amount deposited
t = 1 year is the amount of time
We will plug those values into the formula
i = P*r*t
to get the following:
i = P*r*t
i = 20000*0.065*1
i = 1300
So Mark earns $1,300 in simple interest each year.
Answer:
The answer is C
Step-by-step explanation:
Answer: $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.
Step-by-step explanation:
1. Let's call the amount he got paid per hour at his job as a cashier:
.
Let's call the amount he got paid per hour at his job delivering newspapers:
.
2. Keeping on mind the information given in the problem above, you can make the following system of equations:

3. You can solve it by applying the Substitution method, as following:
- Solve for one of the variables from one of the equations and substitute it into the other equation to solve for the other variable and calculate its value.
- Substitute the value obtained into one of the original equations to solve for the other variable and calculate its value.
4. Therefore, you have:

Then:

Finally:

Therefore he got paid $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.
Answer:
t to the sixth power equals 9
t=1.5
Step-by-step explanation: