Answer:
The answer is A.
Step-by-step explanation:
The only option is A. since an intercept of (-5,0)
Option B has y-int: (0,-5)
Option C has y-int: (0,5)
Option D has x-int(5,0)
Answer:
V = 26d^2 + 624d
Step-by-step explanation:
Volume = Width x Depth x Height
V = 26 (d) (d+24)
Now distribute 26
V = 26d(d+24)
Then distribute 26d
V = 26d^2 + 624d
9514 1404 393
Answer:
5/8
Step-by-step explanation:
The area of the smaller circles is proportional to the square of the ratio of their diameters. The two smallest circles have diameters equal to 1/4 the diameter of the largest circle. Hence their areas are (1/4)^2 = 1/16 of that of the largest circle.
Similarly, the medium circle has a diameter half that of the largest circle, so its area is (1/2)^2 = 1/4 of the are of the largest circle.
The smaller circles subtract 2×1/16 +1/4 = 3/8 of the area of the largest circle. Then the shading is 1-3/8 = 5/8 of the area of the largest circle.
Answer:
12πx⁴, 15x⁷, 16x⁹
Step-by-step explanation:
Volume of a cylinder: πr²h
Volume of a rectangular prism: whl
Plugging in variables for the volume of a cylinder, we get: 3x²·(2x)²·π
3x²·(2x)² = 3·2·2·x·x·x·x
= 12·x⁴
=12x⁴
Now, we just multiply that by π.
12x⁴·π = 12x⁴π
A monomial is a 1-term polynomial, so 12x⁴π is a monomial.
Plugging in variables for the volume of a rectangular prism, we get: 5x³·3x²·x²
5x³·3x² = 5·3·x·x·x·x·x
= 15·x⁵
= 15x⁵
Now, we just multiply that by x².
15x⁵·x²
= 15·x·x·x·x·x·x·x
= 15·x⁷
=15x⁷
A monomial is a 1-term polynomial, so 15x⁷ is a monomial.
Same steps for the last shape, another rectangular prism:
2x²·2x³·4x⁴
2x²·2x³
= 2·2·x·x·x·x·x
= 4·x⁵
= 4x⁵
Now, we just multiply that by 4x⁴.
4x⁵·4x⁴
= 4·4·x·x·x·x·x·x·x·x·x·
= 16·x⁹
= 16x⁹
A monomial is a 1-term polynomial, so 16x⁹ is a monomial.
Answer:
64/3 cc or 64/3 cm³
Step-by-step explanation:
The formula for the volume of a triangular pyramid is
V = (1/3)(area of base)(height)
Here we have a square prism (actually, a cube), whose square base is 4 cm by 4 cm (4 cm is the cube root of 64 cc). The height of this cube is also 4 cm.
The volume of a triangular pyramid of base area (4 cm)² and height 4 cm is
V = (1/3)(base area)(height)
= (1/3)(16 cm²)(4 cm) = 64/3 cc
