Let's say you want to compute the probability

where

converges in distribution to

, and

follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing

such that its mean and variance are the same as those for

.
Example: If

is binomially distributed with

and

, then

has mean

and variance

. So you can approximate a probability in terms of

with a probability in terms of

:

where

follows the standard normal distribution.
Answer:
9: a^8/c^2
Step-by-step explanation:
(a^4/c)^2
(a^8/c^2)
Answer:
Step-by-step explanation:
36x^3 - 81x
9x(4x^2 - 9)
9x(2x - 3)(2x + 3)
She is right
Answer: Hence, the value of expression is 30 when p = 8.
Step-by-step explanation:
Since we have given that

and we have p = 8.
So, we substitute the value of p in the above expression.
so, it becomes,

Hence, the value of expression is 30 when p = 8.