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soldi70 [24.7K]
3 years ago
12

Use inverse operation to solve 116=4n

Mathematics
2 answers:
Anarel [89]3 years ago
8 0
Just divide by 4 on both sides to isolate n, that gets you 29.
zheka24 [161]3 years ago
5 0

Answer: 29

Step-by-step explanation:

116=4n

(Divid both sides by 4)

29=n

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Ramiro drew the graph below.
cluponka [151]
The equation x squared minus 8x+16 represents the data in the graph because if you use the -b/2a x=4. Then if you plug in the 4 for the x in the equation you would come out with the vertex of (4,0). Hope this helps.
4 0
3 years ago
Read 2 more answers
What's 2/5 - 9/10 as a fraction?
elena-s [515]

Answer:

- 1/2

Step-by-step explanation:

turn 2/5 to have the same denominator as 10

2 ( 2 ) = 4

5 ( 2 ) = 10

4/10 - 9/10

= -5/10

simplify

-5/10 = -1/2

hope this helps

4 0
3 years ago
Ram noticed three students used 1 2/10 dm of tape.what was the total used for three students???
OLga [1]

Answer:

18/5

Step-by-step explanation:

<em>From my understanding, this is 1 whole 2 upon 10</em>

<u>Step 1: Convert mixed fraction into fraction</u>

<em>Multiply whole number by denominator: 1 x 10 = 10</em>

<em>Add numerator: 10 + 2 = 12</em>

<em>Write the result as the numerator and use the same denominator.</em>

12/10

<u>Step 2: Find the total tape used</u>

<em>From my understanding, each student used 12/10 of the tap</em>

<em>So 3 students used: 12/10 x 3 =</em> 18/5

Therefore, the total tape used for three students was 18/5.

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7 0
3 years ago
Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

  • a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

  • b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

  • c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

#SPJ4

8 0
2 years ago
What is the center and radius of the circle with equation (x - 2)^2 + (y - 5)^2 = 100?
ololo11 [35]
Answer: 
Center = (2,5)
Radius = 10
Choice A

To find this answer, first write the equation 
(x-2)^2 + (y-5)^2 = 100
into 
(x-2)^2 + (y-5)^2 = 10^2

Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2

We see that (h,k) = (2,5) is the center
and r = 10 is the radius
5 0
3 years ago
Read 2 more answers
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