The answer to this question is 64m
Answer:
7
Step-by-step explanation:
28 35 56
1 and 28 1 and 35 1 and 56
2 and 14 7 and 5 2 and 28
4 and 7 4 and 14
7 and 8
Answer:
temperature of city a=5
temperature of city b=4
Step-by-step explanation:
Given:
Let temperature of city A= a
temperature of city B=b
As given:
4a=8+3b
a-2b=-3
rearranging 2nd equation we get:
a=-3+2b
substituting above in 1st equation we get:
4(-3+2b)-3b=8
8b - 12 = 3b + 8
8b-3b=12+8
5b = 20
b = 4
Now substituting b=4 in 4a = 8 + 3b
, we get
4a = 8 + 3b
4a = 8 + 3(4)
4a = 8 + 12
4a = 20
a = 20/4
a = 5
temperature of city a and city b on that day is 5C and 4C respectively!
The answer to your question would be 'A'
Answer:
m∠QPR = 35° m∠QPM =40° m∠PRS = 30°
Step-by-step explanation:
ΔPRQ is a right triangle with right angle at R. So m∠QPR = 90 - 55 = 35
ΔQPM is a right triangle with right angle at M. So m∠QPM = 90 - 40 = 40
Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.
So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60
Now arc PS is the intercepted arc for ∠PRS.
Therefore, m∠PRS = 60/2 = 30
I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times. Also, I used the fact that the acute angles of a right triangle are complementary. And, finally I used the fact that an inscribed angle in a semicircle is a right angle.
I hope this helped.