Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
Answer:
B: 12.9
Step-by-step explanation:
If A B and C are the alternatives, the answer is B: 12.9
The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.
And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6
Any questions, comment.
Answer: C. (-3, 9)
Step-by-step explanation:
Given
2|x-3|=12
Divide both sides by 2
2|x-3|/2=12/2
|x-3|=6
Take of absolute value sign (REMEMBER need to take into consideration of two conditions)
x-3=±6
1)x-3=6
x=9
2)x-3=-6
x=-3
**NOTE**: need to check each solution whether or not they are suitable
Hope this helps!! :)
Please let me know if you have any questions
Answer: A.
Step-by-step explanation:
Danika has 1/4 lb apple and a 3/16 apple. We have to find a common denominator to be able to subtract them. We can do this by finding out 4 times how much equals 16. Which is 4. So you multiply both of the numbers by 4, (1x4 = 4 , 4x4 = 16) being 4/16. Now you just have to subtract the top numbers "4-3 = 1" 1/16.
Answer:

Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a
, creating right triangles
and
.
The Pythagorean Theorem states that the following is true for any right triangle:
, where
is the hypotenuse, or the longest side, of the triangle
Thus, we have:

Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to 