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valentina_108 [34]
3 years ago
5

Danika has one apple that weighs 1/4 lb and another apple weighs 3/16 lb. Find the DIFFERENCE in their weights.

Mathematics
2 answers:
rosijanka [135]3 years ago
7 0
Answer: a

first you want to convert both into like terms so converting 1/4 to 4/16
then you can subtract accordingly to get 4/16 - 3/16 to get 1/16
hope this helps :)
Mama L [17]3 years ago
4 0

Answer: A.

Step-by-step explanation:

Danika has 1/4 lb apple and a 3/16 apple. We have to find a common denominator to be able to subtract them. We can do this by finding out 4 times how much equals 16. Which is 4. So you multiply both of the numbers by 4, (1x4 = 4 , 4x4 = 16) being 4/16. Now you just have to subtract the top numbers "4-3 = 1" 1/16.

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2 more questions thanks
sergey [27]
These are two questions and two answers.

1) Problem 17.

(i) Determine whether T is continuous at 6061.

For that  you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.

a) T(x) = 0.10x if 0 < x ≤ 6061

T (6061) = 0.10(6061) = 606.1

b) limit of Tx when x → 6061.

By the left the limit is the same value of T(x) calculated above.

By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)

⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10

Since both limits and the value of the function are the same, T is continuous at 6061.

(ii) Determine whether T is continuous at 32,473.

Same procedure.

a) Value at 32,473

T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26

b) Limit of T(x) when x → 32,473 from the right

Limit = 5360.26 + 0.26(x - 32,473) = 5360.26

Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.

(iii) If  T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.

2) Problem 18.

a) Statement Sk

You just need to replace n for k:

Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2

b) Statement S (k+1)

Replace

S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2

Simplification:

1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2

                 k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2

Do the operations on the left side and  you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.

With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.

4 0
3 years ago
Read 2 more answers
Factor the trinomial completely <br><br> 3x^2-5x-2
nignag [31]

Answer:

(x − 2)×(3x+1)

Step-by-step explanation:

We can use this method:

\begin{aligned}3 x^{2}-5 x-2 &=3 x^{2}-5 x-x+x-2 \\\\&=3 x^{2}-6 x+x-2 \\\\&=3 x \cdot(x-2)+(x-2) \\\\&=(x-2)(3 x+1)\end{aligned}

All I did is Subtracting x then adding x which will not affect the result because  -x + x = 0

8 0
2 years ago
I need help with these fast. Will give you brainliest and all my points
Amanda [17]
I am trying hard to help give me a second
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