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Naddik [55]
4 years ago
13

Does the frequency distribution appear to have a normal​ distribution? Explain. Temperature ​(degrees​F) Frequency 35 dash 39 1

40 dash 44 4 45 dash 49 9 50 dash 54 13 Temperature ​(degrees​F) Frequency 55 dash 59 9 60 dash 64 2 65 dash 69 1 Choose the correct answer below. A. ​No, because the frequencies start​ low, proceed to one or two high​ frequencies, then decrease to a low​ frequency, and the distribution is not symmetric. B. ​No, because the frequencies start​ low, proceed to one or two high​ frequencies, then decrease to a low​ frequency, and the distribution is approximately symmetric. C. ​Yes, because the frequencies start​ low, proceed to one or two high​ frequencies, then increase to a​ maximum, and the distribution is not symmetric. D. ​Yes, because the frequencies start​ low, proceed to one or two high​ frequencies, then decrease to a low​ frequency, and the distribution is approximately symmetric.

Mathematics
1 answer:
AlexFokin [52]4 years ago
5 0

Answer:

D. ​Yes, because the frequencies start​ low, proceed to one or two high​ frequencies, then decrease to a low​ frequency, and the distribution is approximately symmetric.

Step-by-step explanation:

Hello!

The given frequency distribution for temperatures.

To see if the distribution appears to have a normal distribution you have to draw a histogram using the information. Check attachment.

As you can see, the distribution appears symmetric, it starts low and proceeds to grow until it reaches its maximum point (f(4)=13) and then starts to decrease to low frequencies. The right tail decreases a little more than the left one but it is almost symmetrical.

I hope this helps!

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Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

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c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

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D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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