Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
<span>(f o g)(4) = f(g(4))
so
g(4) = </span><span>-2(4) -6 = -14
</span>f(g(4)) = <span>3(-14) -7 = -49
answer
</span><span> (f o g)(4) = -49</span>
Answer:
106
Step-by-step explanation:
So ... notice the picture below... the ratio is 3:1 from C to D, meaning the segment CE takes 3 units, whilst the ED segment takes 1
anyhow
Answer:
30
Step-by-step explanation:
60/40=3/2
105/40+x = 3/2
105/70=3/2
x=70-40 = 30
