If you do the calculations and have in mind the data given then we may say that 1) The company must sell 250 cameras in one day and
2) If the manufacturer increases the production by 50 then the profut would be 400.
Your option is the first one, option A
Answer: like wheres the graph
do u have a graph
Step-by-step explanation:
3) 3.sec² Ф = 4.tan² Ф
but sec² Ф = 1/cos² Ф
3/cos² Ф = 4.tan² Ф
3/4 = (tan² Ф).(cos² Ф) ; tan² Ф = sin² Ф/cos² Ф
3/4 = (sin² Ф)x(cos² Ф)/(cos² Ф)
sin² Ф = 3/4
a) sin Ф = +(√3)/2 and b) sin Ф = - (√3)/2
sin Ф = + - (√3)/2 → Ф =π/3 + kπ/3
Answer:c
Step-by-step explanation:
Answer:
Step-by-step explanation:
Find the midpoint of each frequency range, multiply that number by the frequency, sum up and divide by the total frequency.
This will give the mean number.
<u>The mean is:</u>
- [17*( 3 + 3.5)/2 + 21*(3.5 + k)/2 + 33*(k + 4)/2 + 54*(4 + 4.5)/2 + 15*(4.5 + 6)/2]/140 = 4.09
- 55.25 + 10.5k + 36.75 + 16.5k + 66 + 229.5 + 78.75 = 140*4.09
- 17k + 466.25 = 572.6
- 17k = 572.6 - 466.25
- 17k = 106.35
- k = 106.35/17
- k = 6.26
Note, I expected the value of k between 3.5 and 4. This is a bit of illogical outcome.
