Answer:
The area of the figure = 112 in²
Step-by-step explanation:
The figure consist of:
1) A square of side length of 10 in.
2) A right triangle with a base of (10 - 6 = 4 in) and a height of (16 - 10 = 6 in)
So,
The area of the square = (side length)² = 10² = 100 in²
The area of the triangle = 0.5 * height * base = 0.5 * 6 * 4 = 12 in²
So,
The total area = 100 + 12 = 112 in²
<u>The area of the figure = 112 in²</u>
See the attached figure
we know that
MN=16 in-------------> PQ=MN
PQ=16 in
<span>L is the midpoint of PQ-----------> distance QL=</span><span>PQ/2
QL=8 in
if </span>m∠QLM = 45°
then
MQ=QL
MQ=8 in
Perimeter=[MN]*2+[MQ]*2=16*2+8*2=48 in
the answer is 48 in
<span>-5x+2y=10
They both have the same slopes:)
</span>
Answer:
x=12
Step-by-step explanation:
If the triangles are similar:
x/8=18/12
x/8=1.5
x=12
Answer:
The distance between the greater sides is 4.8 cm
Step-by-step explanation:
step 1
Find the area of parallelogram
we know that
the perpendicular distance between the smaller sides is also the height of parallelogram
The area of parallelogram is equal to multiply the length of the smaller side by the perpendicular distance between the smaller sides
so

step 2
Find out the distance between the greater sides
we know that
The area of parallelogram is equal to multiply the length of the greater side by the perpendicular distance between the greater sides
Let
x ----> the perpendicular distance between the greater sides
so

we have

substitute

solve for x
