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FinnZ [79.3K]
3 years ago
9

Help! I will give thanks!

Mathematics
2 answers:
enyata [817]3 years ago
6 0
Mode = 60

Reason: 60 appeared 4 times.
drek231 [11]3 years ago
3 0
6\000= 60  7/00=70 8/00 =80 9/0=90
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A store owner purchases thirty 75-watt light bulbs and 40 fluorescent light bulbs for a total cost of $95. A second purchase, at
N76 [4]

Answer:   75-watt are 30$  fluorescent are 30$ in the second and 65$ in the first

     

Step-by-step explanation: i calculated thirty 75-watt and the fluorescent and got these kinda hard to explain hope i helped:)

7 0
3 years ago
Order from least to greatest .9, 8/9, .86
labwork [276]

Answer:

<em>least</em><em> </em><em>to</em><em> </em><em>greatest</em>

<em>.</em><em>86</em><em>,</em><em> </em><em>8</em><em>/</em><em>9</em><em>,</em><em> </em><em>.</em><em>9</em>

8 0
3 years ago
Read 2 more answers
How should the decimal point in 52.48 be moved to determine the product 52.48×105 ?
tensa zangetsu [6.8K]

Answer:

5510.4

Step-by-step explanation:

4 0
3 years ago
Oliver climbed 222 meters of a steep mountain reach the summit. He then rappelled down the other side of the mountain to return
nikdorinn [45]
B -222

Because he fell/descended 222 meters. And falling or going down produces a negative integer. Also, if you were actually doing the math to try to find where Oliver is currently located, you wouldn't add 222, or 0, or subtract -444. You would subtract 222. 

In addition, be aware that the question is asking you an integer to represent a situation, not the answer of where Oliver is. 

6 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
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