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3 years ago

What are the solutions to log5(x + 5) = x2

Mathematics

2 answers:

valentinak56 [21]3 years ago

4 0

The answers should be A and D

katrin [286]3 years ago

3 0

Answer:

A and D on edg

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A small square of side 2x is cut from the corner of a rectangle with a width of 10 centimeters and length of 20 centimeters. Wri

love history [14]

Find the area of the rectangle. You can find the area of a rectangle with the following formula:

$A = wl$

w = width, and l = length.

Plug in your width and length:

$20 * 10 = 200$

The area of the rectangle is 200 square centimeters.

The area of a square is also given by width * length. Multiply the sides together:

$2x * 2x = 4x^{2}$

The area of a square is 4x^2.

Because you're cutting away the square from the rectangle, you will subtract the area of the square from the area of the rectangle. The following equation will be your answer:

$200 - 4x^{2} cm^{2}$

6 0

3 years ago

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

3 years ago

Convert 7.7km into miles if 1.6 km = 1 mile

Lemur [1.5K]

This is a simple equation.

The equation is y = 1.6x with y being the miles and x being the kilometers.

Lets plug the kilometers in.

Y=1.6(7.7)

1.6 * 7.7 = 12.32

12.32 miles is equal to 7.7 kilometers

HOWEVER

There are about .6 miles in a kilometer, so if you typed this wrong I don't know.

It is still the same concept.

Y = .6x

Y = .6(7.7)

.6 * 7.7 = 4.8

In this case there are 4.8 miles in 7.7 kilometers

3 0

2 years ago

A normal distribution has a standard deviation equal to 39. What is the mean of this normal distribution if the probability of s

Naily [24]

Answer:

The mean is $\mu = 131$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\sigma = 39$