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creativ13 [48]
3 years ago
13

The derivative of the function f is given by f′(x)=−3x+4 for all x, and f(−1)=6. Which of the following is an equation of the li

ne tangent to the graph of f at x=−1? I think it’s y=7x+13, but I could just be delusional
Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

You are correct. The answer is y=7x+13

Step-by-step explanation:

First, we need to plug in our x value to the derviative's equation to find the slope of the line tangent to the graph, f

f'(x)=-3x+4\\\\f'(-1)=-3(-1)+4\\\\f'(-1)=3+4\\\\f'(-1)=7

Now that we have found the slope and have a given point: (-1,6) we can use the point slope formula to find the equation of the line tangent to the graph f.

y-6=7(x+1)\\\\y-6=7x+7\\\\y=7x+13

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Solve for . Simplify your answer as much as possible. please help
Sonja [21]

Answer:

x=-6

Step-by-step explanation:

So we have the equation:

-34=7(x+8)+8x

First, distribute the 7 into the (x+8) and simplify:

-34=7(x)+7(8)+8x\\-34=7x+56+8x

Combine the like terms 7x and 8x by adding them together:

-34=56+15x

Subtract 56 from both sides to isolate the x:

-34-56=15x+56-56\\15x=-90

Divide both sides by 15 to get x:

x=-90/15=-6

5 0
3 years ago
PLSSSS HELPPP<br><br> 4 ¼ divided by 2 ½
notsponge [240]

Answer:

1.7 or 1 7/10

Step-by-step explanation:

5 0
2 years ago
A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute
nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

P(k\geq8)=1-P(k

P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\

P(k

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002

5 0
3 years ago
3^5 equals 243. Explain how to use that fact to quickly evaluate 3^6.
OlgaM077 [116]

Answer:

Simply multiply 243 with 3.

Step-by-step explanation:

3^6=729

243*3=729

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3 years ago
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Step-by-step explanation:

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