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katrin2010 [14]
3 years ago
15

IF YOU DON"T KNOW DON"T ANSWER! (unless you make me laugh, then we're good.) Describe the apparatus and the values graphed.

Chemistry
1 answer:
Schach [20]3 years ago
7 0

lol im a senior in high school (12th grade) and I dont even know this stuff or i forgot it either way im pretty sure im just dumb

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Propane has a normal boiling point of -42.04 °C and a heat of vaporization of 24.54 kJ/mole. What is the vapor pressure of propa
Mademuasel [1]

Answer : The vapor pressure of propane at 25.0^oC is 17.73 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of propane at 25.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 25.0^oC=273+25.0=298.0K

T_2 = normal boiling point of propane = -42.04^oC=230.96K

\Delta H_{vap} = heat of vaporization = 24.54 kJ/mole = 24540 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{24540J/mole}{8.314J/K.mole}\times (\frac{1}{298.0K}-\frac{1}{230.96K})

P_1=17.73atm

Hence, the vapor pressure of propane at 25.0^oC is 17.73 atm.

3 0
3 years ago
Does this seem like a good hypothesis?
kondaur [170]
Yeah it uses some valuable scientific vocabulary and background knowledge, I hope this hypothesis will be good enough for your teacher (don't worry it will be)
6 0
3 years ago
Taken all together the reactions of the human body are
jasenka [17]
The reactions of the human body are exothermic
8 0
3 years ago
50 POINTS!!! DUMB ANSWERS WILL BE DELETED
Verdich [7]

Answer:

hijdjdjdjjdjdidiksjdjdjdjdjdsjjsjksdk

6 0
3 years ago
How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?
Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid \rm H_2SO_4 is a diprotic acid. When one mole of \rm H_2SO_4 molecules dissolve in water, two moles of \rm H^{+} ions would be produced.

\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}.

On the other hand, sodium hydroxide \rm NaOH is a monoprotic base. When one mole of \rm NaOH formula units dissolve in water, only one mole of hydroxide ions \rm OH^{-} would be produced.

\rm NaOH \to Na^{+} + OH^{-}.

Note that \rm H^{+} and \rm OH^{-} react at a one-to-one ratio:

\rm H^{+} + OH^{-} \to H_2O.

As a result, it would take 2\; \rm mol of \rm OH^{-} to react with the \rm 2\; mol of \rm H^{+} that was released when 1\; \rm mol of \rm H_2SO_4 is dissolved in water. Since one mole of \rm NaOH formula units could produce only one mole of \rm OH^{-}, it would take \rm 2\; mol of \rm NaOH formula units to produce that 2\; \rm mol of \rm OH^{-} for reacting with 1\; \rm mol of \rm H_2SO_4.

3 0
3 years ago
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