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kap26 [50]
3 years ago
11

What is the mass of 2.50 moles of NaCl

Chemistry
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

The mass of 2,50 moles of NaCl is 146, 25 g.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate the mass of 2.50 moles of compound, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl=  23 g+ 35,5 g= 58, 5 g/ mol

1 mol ------ 58, 5 g

2,5 mol---x= (2,5 mol x 58, 5 g)/ 1 mol = <u>146, 25 g</u>

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Consider the following reaction at equilibrium. What effect will increasing the pressure of the reaction mixture have on the sys
zaharov [31]

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No effect will be observed.

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8 0
3 years ago
What is the pH of a 0.0288 M solution of ammonia (Kb 1.8 x 10-5)?
elena-14-01-66 [18.8K]

Answer:

10.86

Explanation:

Given that:

K_{b}=1.8\times 10^{-5}

Concentration = 0.0288 M

Consider the ICE take for the dissociation of ammonia as:

                                      NH₃    +   H₂O    ⇄     NH₄⁺ +    OH⁻

At t=0                          0.0288                             -              -

At t =equilibrium        (0.0288-x)                         x           x            

The expression for dissociation constant of ammonia is:

K_{b}=\frac {\left [ NH_4^{+} \right ]\left [ {OH}^- \right ]}{[NH_3]}

1.8\times 10^{-5}=\frac {x^2}{0.0288-x}

x is very small, so (0.0288 - x) ≅ 0.0288

Solving for x, we get:

x = 7.2×10⁻⁴  M

pOH = -log[OH⁻] = -log(7.2×10⁻⁴) = 3.14

Also,

pH + pOH = 14

So, pH = 10.86

3 0
3 years ago
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