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Harrizon [31]
3 years ago
10

What is another name for a flask

Chemistry
2 answers:
amid [387]3 years ago
6 0

Answer:

Bottle, thermos, container, vessel

Explanation:

Semmy [17]3 years ago
5 0

Answer:

the another name for a flask is container

Explanation:

I hope it helped

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Plzz help<br> its science
Aleks04 [339]

The efficiency : 95%

<h3>Further explanation</h3>

Efficiency : the ratio between output and input work

In general, the value of the output of a machine is less than the value of the input because of the frictional force in the machine.

The greater the efficiency of the engine, the better the machine

Can be formulated :

\tt E=\dfrac{W_{out}}{W_{in}}\times 100\%

w output = 190 J

W input = 200 J

The efficiency :

\tt E=\dfrac{190}{200}\times 100\%=95\%

7 0
3 years ago
The temperature of a 500. ml sample of gas increases from 150. k to 350. k. what is the final volume of the sample of gas, if th
Andreas93 [3]
<span>Answer: 1170 ml is the final volume of the sample of gas, if the pressure and moles in the container is kept constant.</span>
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4 years ago
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How many significant figures are in 0.0231?? a lot of points!!!
Lubov Fominskaja [6]

Answer:

3

Explanation:

7 0
4 years ago
The volume of a gas held at constant temperature varies indirectly as the pressure of the gas. If the volume of a gas is 1200 cu
kvasek [131]

Answer:

Volume of the gas at 500 mm Hg pressure is 960 cm^{3}

Explanation:

Let's assume the gas behaves ideally.

According to combined gas law for an ideal gas-

                  \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Where P_{1} and  P_{2} are initial and final pressure of the gas respectively.  V_{1} and  V_{2} are initial and final volume of the gas respectively.  T_{1} and  T_{2} are initial and final temperature of the gas in kelvin respectively.

Here T_{1} = T_{2}, V_{1} = 1200 cm^{3}, P_{1} = 400 mm Hg, P_{2} = 500 mm Hg

So, V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}

Hence V_{2}=\frac{400\times 1200}{500}[tex]cm^{3}=960 cm^{3}[/tex]

Hence volume of the gas at 500 mm Hg pressure is 960 cm^{3}

3 0
4 years ago
Question:<br> What is the molar concentration of 1.29 mol of KCL dissolved in 350 mL of solution?
STatiana [176]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

M=\frac{1.29mol}{0.350L}\\\\M=3.69M

Which gives molar units, M, or just mol/L.

Regards!

8 0
3 years ago
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