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3 years ago

13

Heyyyywooo Friends Can Yall Plz Help

1 answer:

VARVARA [1.3K]3 years ago

3 0

Answer:

I think the answer is A

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When ash, cinders, and bombs build up in a steep pile around a volcano’s vent, the result is a

Verdich [7]

Im pretty sure a cinder-cone volcano

8 0

3 years ago

What does the symbol (–Delta.Hfus) indicate in a phase change?

Rufina [12.5K]

Answer:

changes from a solid to a liquid

Explanation:

8 0

3 years ago

If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH

KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

$M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)$

$M_{KOH}=0.113 M\\V_{KOH}=79.06 mL$

$V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????$

$M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}$

$M_{CH3COOH} = \frac{0.113*79.06}{95.27}$

$M_{CH3COOH} = 0.094 M$

Moles of $CH_3COOH$ = $95.27* 10^{-3}* 0.094$

=0.0090 moles

Moles of $KOH = 79.06*10^{-3}*0.113$

= 0.0090 moles

The equation for the reaction can be expressed as :

$CH_3COOH$ $+$ $KOH$ -----> $CH_3COO^{-}K^+$ $+$ $H_2O$

Concentration of $CH_3COO^{-$ ion = $\frac{0.0090}{Total volume (L)}$

= $\frac{0.0090}{(95.27+79.06)} *1000$

= 0.052 M

Hydrolysis of $CH_3COO^{-$ ion:

$CH_3COO^{-$ $+$ $H_2O$ -----> $CH_3COOH$ $+$ $OH^-$

$K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}$

⇒ $\frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}$

= $0.5494*10^{-9}= \frac{x*x}{0.052-x}$

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

$0.5494*10^{-9}= \frac{x^2}{0.052}$

$x^2 = 0.5494*10^{-9}*0.052$

$x^2 = 0.286*10^{-10$

$x = \sqrt{0.286*10^{-10$

$x =0.535*10^{-5}M$

$[OH] = x =0.535*10^{-5}$

$pOH = -log[OH^-]$

$pOH = -log[0.535*10^{-5}]$

$pOH = 5.27$

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0

3 years ago

Plz help ......<br><br>Na+ has completely filled k and L shells . explain<br>

inessss [21]

Explanation:

Na represents the neutral element; Sodium. Because of it's atomic number of 11, It has 11 electrons.

Na+ on the other hand represents a cation. The sodium ion has lost an electron, hence the total number of electrons it has = 10.

The K and L shells each have maximum number of electrons they can accommodate. This is given by the formular; 2n^2

K shell = 2 (1)^2 = 2 electrons

L shell = 2 (2)^2 = 8 electrons

Seeing as Na+ has 10 electrons, It completely filled the K and L shells ( 2 + 8 = 10 )

5 0

3 years ago

What will be the volume of a balloon at 98K PA if the volume is 9.6 5L at 235KPA

Shtirlitz [24]

Answer:

23.14 L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

8 0

3 years ago