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ArbitrLikvidat [17]
2 years ago
5

A word problem for 460 - 65x < 100

Mathematics
1 answer:
gtnhenbr [62]2 years ago
3 0

<h3>Answer</h3>

\sf \large \:  \green{↬}460 - 65x < 100

\:  \:  \:

Subtract 460 from both sides:

\sf \large \:  \green{↬}460 - 65x - 460 < 100 - 460

\:  \:

\sf \large \:  \green{↬} - 6x + 460 - 460 < 100 - 460

\:  \:

\sf \large \:  \green{↬} - 65x < 100 - 460

\:  \:  \:

\sf \large \:  \green{↬}65x <  - 360

\:  \:  \:

Hope Helps! :)

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The graph of y = sine (x minus StartFraction 3 pi Over 2 EndFraction) is the graph of the y = sin(x) shifted in which direction?
sukhopar [10]

Answer: shifted by  3*pi/2 units to the right.

Step-by-step explanation:

Here we have:

y = sin(x - 3*pi/2)

now, you need to remember this:

if we have y = f(x)

then y' = f(x - A) is the graph of y, shifted A units to the right (where A is a positive number).

If A is negative, the shift is to the left.

Then in this case, we have:

sin(x) -----> sin( x - 3*pi/2)

A = 3*pi/2

Then we have the graph shifted by  3*pi/2 units to the right.

7 0
3 years ago
Read 2 more answers
FIND THE AREA OF THE SECTOR 15 points
ale4655 [162]

Answer:

<u>2.1 m²</u>

Step-by-step explanation:

<u>Area of Sector</u>

  • πr² x α/360°
  • 3.14 x 8 x 30/360
  • 25.12 x 1/12
  • 2.09333333
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4 0
2 years ago
1. A waste management service attempts to design routes so that each of their trucks pick-up on average four tons of garbage or
IRINA_888 [86]

Answer:

1.-Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- p  = 75 %

3.-3.-t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

Step-by-step explanation:

1.- If p-value is 0,04   and significance level α = 5 %  or  α = 0,05 then p-value < α

Test hypothesis should be    ( x the average of garbage)      

Null hypothesis          H₀           x = 4 Tn

Alternative Hypothesis     Hₐ    x  > 4 Tn

Then  alternative hypothesis suggests a one tail-test to the right  and

p-value <  0,05

Then we p-value indicates that we are in the rejection region we reject H₀

We support the claim of the garbage collector the average picking up more than 4 tn of garbage

2.- As we are dealing with a normal distribution the CI  95 % is symmetrical with respect to the mean, therefore the proportion of student living in Brooklyn is:  

(0,73 + 0,77) /2

p = 0,75     p  = 75 %

Test hypothesis:

Null Hypothesis            H₀            μ    =  26

Alternative Hypothesis      Hₐ      μ   <  26

Alternative hypothesis tells us the test is a one-tail test to the left

Sample size   n = 25

Sample mean   μ  =  24,4

Sample Standard deviation  =  9,2

We assume normal distribution, and as n < 30 we use t-student table

with  24 degree of freedom

Significance level is 0,05  and df = 24  we find t (c)  in t- student table

t(c) = 1,7109      test to the left   t(c) = -1,7109

To calculate  t(s)

t(s)  =  (  24,4 - 26 ) / 9,2 / √25

t(s) =  - 1,6 * 5 / 9,2

t(s) = - 0,87

Comparing t(s)  and t(c) we have

t(s) > t(c)

t(s) is in the rejection region we accept H₀ we have not evidence to support Marc´s claim

6 0
2 years ago
A large company claims that the average age of their employees is 32 years, with a standard deviation of 4 years. The average ag
4vir4ik [10]

Given that average age of employees of a large company is Normal

X - average age of employees

X:N(32,4)

The average age of employees in sales dept is 27 years.

Prob that an employee, chosen at random, will be younger than 27 years.

= P(X<27)

Let us convert x into Z

Z = (x-32)/4 = -5/4 = -1.25

Reqd prob = P(Z<-1.25) =0.5-0.3925

= 0.1075

Hence 10.56% is the correct answer.

3 0
3 years ago
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Please solve<br>x^2+x-6006=0​
Ratling [72]

Step-by-step explanation:

x^2+x-6006=0

x^2+78x-77x-6006=0

x(x+78)-77(x+78)=0

(x-77)(x+78)=0

=>x=77 or x=78

7 0
3 years ago
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