The dimensions of a rectangular garden were 3 m by 10 m. When both dimensions were increased by equal amounts, the area of the g
arden doubled. Find the dimensions of the new garden.
1 answer:
A=l*w
A=3*10
30=A
add x to l and w the area doubled
60 = (3+x)(10+x)
FOIL
60 = 30 +3x+10x+x^2
60 = x^2 +13x+30
subtract 60 from each side
0=x^2 +13x-30
factor
0=(x+15) (x-2)
x+15=0 x-2=0
x=-15 x=2
x cannot be negative so x=2
new dimensions
3+2, 10+2
Answer: 5m ,12m
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