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lapo4ka [179]
3 years ago
7

The dimensions of a rectangular garden were 3 m by 10 m. When both dimensions were increased by equal amounts, the area of the g

arden doubled. Find the dimensions of the new garden.
Mathematics
1 answer:
Helen [10]3 years ago
4 0

A=l*w

A=3*10

30=A

add x to l and w the area doubled

60 = (3+x)(10+x)

FOIL

60 = 30 +3x+10x+x^2

60 = x^2 +13x+30

subtract 60 from each side

0=x^2 +13x-30

factor

0=(x+15) (x-2)

x+15=0  x-2=0

x=-15  x=2

x cannot be negative so x=2

new dimensions

3+2, 10+2

Answer: 5m ,12m

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7 0
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Read 2 more answers
What is the quotient (6x4 − 15x3 − 2x2 − 10x − 4) ÷ (3x2 + 2)?
wariber [46]

we are given

(6x^4-15x^3-2x^2-10x-4)  ÷  (3x^2+2)

we can divide it by using long division method

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..............Answer


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