Question

A radiator contains 8 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?

Answer 1

Answer: 1.6 quarts

Step-by-step explanation:

Given : A radiator contains 8 quarts of fluid, 40% of which is antifreeze.

[40% can be written as 0.40.]

Then, the amount of antifreeze in radiator = $0.40\times8=3.2\text{ quarts}$                                                                                              (1)

 

If a radiator contains 8 quarts of fluid with 60% of which is antifreeze.

[60% can be written as 0.60.]

Then, the amount of antifreeze in radiator = $0.60\times8=4.8\text{ quarts}$                                                                                             (2)

 

Now subtract (1) from (2) we get,

The amount of fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze :-

$4.8-3.2=1.6\text{ quarts}$

Hence, the 1.6 quarts of fluid should be drained  and replaced with pure antifreeze so that the new mixture is 60% antifreeze

Answer 2

Answer:1.6 of a container of the fluid mustbe drained to make it 60% anti-freeze

Step-by-step explanation: