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user100 [1]
4 years ago
11

A radiator contains 8 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antif

reeze so that the new mixture is 60% antifreeze?
Mathematics
2 answers:
VladimirAG [237]4 years ago
7 0

Answer: 1.6 quarts

Step-by-step explanation:

Given : A radiator contains 8 quarts of fluid, 40% of which is antifreeze.

[40% can be written as 0.40.]

Then, the amount of antifreeze in radiator = 0.40\times8=3.2\text{ quarts}                                                                                              (1)

 

If a radiator contains 8 quarts of fluid with 60% of which is antifreeze.

[60% can be written as 0.60.]

Then, the amount of antifreeze in radiator = 0.60\times8=4.8\text{ quarts}                                                                                             (2)

 

Now subtract (1) from (2) we get,

The amount of fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze :-

4.8-3.2=1.6\text{ quarts}

Hence, the 1.6 quarts of fluid should be drained  and replaced with pure antifreeze so that the new mixture is 60% antifreeze

Alenkinab [10]4 years ago
5 0

Answer:1.6 of a container of the fluid mustbe drained to make it 60% anti-freeze


Step-by-step explanation:


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