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liubo4ka [24]
3 years ago
14

Just two more thanks for all the help thus far

Mathematics
1 answer:
guapka [62]3 years ago
3 0

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

You might be interested in
Find the least common denominator. Then express each fraction using the least common denominator.
Rudiy27

Answer:

THE LCM OF 15 AND 20 IS 60

1/60 AND 3/60

Step-by-step explanation:

5 0
3 years ago
Decide whether the normal sampling distribution can be used. If it can be​ used, test the claim about the population proportion
soldi70 [24.7K]

Answer:

np=25*0.11=2.75 < 10

n(1-p)=25*(1-0.11)=22.25 > 10

Th second condition is satisfied but the first one on this case it's not satisfied. So for this case it's not good apply the normal approximation to the distribution of p.

Step-by-step explanation:

We need to check the conditions in order to use the normal approximation.

np=25*0.11=2.75 < 10

n(1-p)=25*(1-0.11)=22.25 > 10

Th second condition is satisfied but the first one on this case it's not satisfied. So for this case it's not good apply the normal approximation to the distribution of p.

If we have both conditions satisfied the general procedure is the following:

Data given and notation

n=23 represent the random sample taken

\hat p=0.08 estimated proportion

p_o=0.11 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.11.:  

Null hypothesis:p \geq 0.11  

Alternative hypothesis:p < 0.11  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

On this case since the normal approximation it's not satisfid it's not correct calculate the statistic.

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

And if the p_v we reject the null hypothesis. Otherwise w fail to the reject the null hypothesis.

5 0
3 years ago
Levi wants to order the fractions 1/3, 2/5, and 11/30 in descending order? How can you help him by using a common denominator? E
Georgia [21]

Answer:

The correct order of fractions in descending order will be:

\frac{2}{5}, \frac{11}{30}, \frac{1}{3}

Step-by-step explanation:

Given fraction:

\frac{1}{3}, \frac{2}{5}, \frac{11}{30}

To arrange them in descending order.

Solution:

In order to arrange the fractions in descending order, we will have to find the least common denominators.

To find the least common denominator, we will find the least common multiple of the denominators 3,5, and 30.

Since 30 is a common multiple of all 3 numbers, so it will be the least common denominator.

So, we multiply the numerators and denominators with same numbers in order to make the denominators = 30.

So, we have:

\frac{1}{3}, \frac{2}{5}, \frac{11}{30}

⇒ \frac{1\times 10}{3\times 10}, \frac{2\times 6}{5\times 6}, \frac{11\times 1}{30\times 1}

⇒ \frac{10}{30}, \frac{12}{30}, \frac{11}{30}

Now, we compare the numerators and arrange them accordingly.

\frac{12}{30} > \frac{11}{30} > \frac{10}{30}

So, the correct order of fractions in descending order will be:

\frac{2}{5}, \frac{11}{30}, \frac{1}{3}

3 0
3 years ago
Convert the following to scientific notation<br> A) 0.315<br> B) 5,820,000,000
Savatey [412]

Answer:

Step-by-step explanation:

a. 0.315 = 3.15 x 10^-1

b. 5,820,000,000 = 5.82 x 10^9

3 0
3 years ago
A group of entomologists has determined that the population of ladybugs at a local park can be modeled by the equation y = − 1.4
Oksanka [162]
<h3>Answer:</h3>

A) 177.568 thousand.

B) 125.836 thousand.

<h3>Step-by-step explanation:</h3>

In this question, it is asking you to use the equation to find the population of ladybugs in a certain year.

Equation we're going to use:

y = -1.437 x + 197.686

We know that the "x" variable represents the number of years since 2010, so that means our starting year is 2010.

Lets solve the question.

Question A:

We need to find the ladybug population is 2024.

2024 is 14 years after 2010, so our "x" variable will be replaced with 14.

Your equation should look like this:

y = -1.437 (14) + 197.686

Now, we solve.

y = -1.437 (14) + 197.686\\\\\text{Multiply -1.437 and 14}\\\\y=-20.118+197.686\\\\\text{Add}\\\\y=177.568

You should get 177.568

This means that the population of ladybugs in 2024 is 177.568 thousand.

Question B:

We need to find the ladybug population is 2060.

2060 is 50 years after 2010, so the "x" variable would be replaced with 50.

Your equation should look like this:

y = -1.437 (50) + 197.686

Now, we solve.

y = -1.437 (50) + 197.686\\\\\text{Multiply -1.437 and 50}\\\\y=-71.85+197.686\\\\\text{Add}\\\\y=125.836

This means that the population of ladybugs in 2060 would be 125.836 thousand.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
7 0
4 years ago
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