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cupoosta [38]
3 years ago
11

What is two minus Parentheses eight -5×6 parentheses?

Mathematics
2 answers:
Reil [10]3 years ago
6 0
-20 order of operations shows that we would do pemdas 2-(8-5*6)
-5*6=-30
8-30=-22
2-(-22)=-24
kiruha [24]3 years ago
4 0

Answer: 24

Step-by-step explanation:

2-(8-5x6) = 24

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If y is 15 times x, which equation shows the relationship between x and y?
zhannawk [14.2K]
Is= equals sign
times= multiplication


So y equals 15 times x

y= 15 * x
y= 15x


ANSWER: y= 15x (bottom choice)

Hope this helps! :)
4 0
3 years ago
A courier service advertises that its average delivery time is less than six hours for local deliveries. A random sample of size
Diano4ka-milaya [45]

Answer, Step-by-step explanation:

According to the exercise, we evaluate the delivery time of a courier company and we will hypothesize the best case with a sample size of 10, which is:

Small sample T test for single mean

The hypothesis that we will develop will be the following:

null hypothesis = mu> = 6

hypothesis alternativa: <6

3 0
3 years ago
1. 25% of what is 16 2. 76 is what percent of 80
Allisa [31]
1.64
2. 95%
Hope this helps you.
6 0
3 years ago
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
0.45 repeating as a fraction
stira [4]
0.9090909.../2
This is the equivalent and it has no equal fraction counterpart
4 0
3 years ago
Read 2 more answers
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